Degree of the polynomial $(x^{3} - 2) (x^{2} + 11)$ is

0

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5

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3

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2

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Solution

The correct option is B $5$
The degree of a polynomial is the highest degree of its monomials (individual terms) with non-zero coefficients.

The degree of a term is the sum of the exponents of the variables that appear in it, and thus is a non-negative integer.

Now, $(x^{3} - 2) (x^{2} + 11)$
$= x^{5} + 11 x^{3} - 2 x^{2} - 22$

Here, $x^{5}$ is the monomial with highest power.
So, degree $= 5$

Hence, $B$ is correct.

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Similar questions

[x + (x^{3} - 1)^{1 / 2}]^{5} + [x - (x^{3} - 1)^{1 / 2}]^{5}

[x + (x^{3} - 1)^{1 / 2}]^{5} + [x - (x^{3} - 1)^{1 / 2}]^{5}

{{x + (x^{3} - 1)}^{1 / 2}}^{5} + {{x - (x^{3} - 1)}^{1 / 2}}^{5}

Find the degree of the polynomial

${(x + (x^{3} - 1)^{\frac{1}{2}})}^{5} + {(x - (x^{3} - 1)^{\frac{1}{2}})}^{5}$

\frac{x^{3} + 2 x + 1}{5} - \frac{7}{2} x^{2} - x^{6}

x^{3}

x^{6}

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