Dehydration of the alcohols will be in order:

I V > I I I > I I > I

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I > I I > I I I > I V

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I V > I I > I I I > I

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I I > I V > I > I I I

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Solution

The correct option is D $I V > I I > I I I > I$
The dehydration of tertiary alcohol is faster than the dehydration of the secondary alcohol.

Also, the dehydration of the secondary alcohol is faster than the dehydration of primary alcohol.

Thus, the order of dehydration is $I V (t e r t i a r y a l c o h o l) > I I (s e c o n d a r y a l c o h o l) > I I I (s e c o n d a r y a l c o h o l) > I (p r i m a r y a l c o h o l)$ .

The alcohol $I I$ is more easily dehydrated than the alcohol $I I I$ as in the alcohol $I I$ , the secondary carbocation has 5 alpha hydrogen atoms takes part in hyperconjugation while in $I I I$ there are only 3 alpha hydrogens.

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Similar questions

Q. Arrange the following alcohols in the decreasing order of their ease of dehydration with

H_{2} S O_{4}

Arrange the following alcohols in order of increasing ease of dehydration
$C H_{3} C H_{2} O H$ $C_{6} H_{5} C H_{2} O H$
I II

$C l_{3} C C H_{2} O H$ $F_{3} C C H_{2} O H$
III IV

Correct order for the rate of dehydration for the given compound with

H_{2} S O_{4}

is:

In the following molecules:
$C H_{3} B r, C H_{3} F, C H_{3} C l, C H_{3} I I, I I, I I I, I V$
The correct order of dipole moment will be:

The order of -I power (-ve inductive effect ) of the following functional groups will be:

(i) $- S O_{3} H$

(ii) $- C l$

(iii) $- N H_{2}$

(iv) $- H$

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