Dehydrohalogenation of ethyl chloride in presence of alc. KOH produces the following :

H C \equiv C H + K C l + H_{2} O

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{C H}_{4} + K C l + H_{2} O

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{C H}_{2} = {C H}_{2} + K C l + H_{2} O

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C_{2} H_{4} + H C l

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Solution

The correct option is C ${C H}_{2} = {C H}_{2} + K C l + H_{2} O$
Reaction of the process: $C H_{3} - C H_{2} C l + K O H \to C H_{2} = C H_{2} + K C l + H_{2} O$
In this process Alc. $K O H$ is used for dehydrohalogenation.

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Similar questions

K_{2} C O_{3} + H C l \to

Fill in the blank:
$K_{2} C O_{3} + H C l \to$ ___________

C l_{2} + K O H \to K C l O_{3} + K C l + H_{2} O

K M n O_{2} + H C l \to K C l + M n C l_{2} + H_{2} O + C l_{2}

N H_{3} + O_{3} \to N O + H_{2} O

K_{2} C O_{3}

H C l

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