Delocalization of electrons increases molecular stability because ________________.

Potential energy of the molecule decreases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Electron-nuclei attraction decreases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both (A) and (B)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Electron-electron repulsion increases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Both (A) and (B)
Delocalization increases molecular stability. Due to resonance, the potential energy of the molecule decreases by spreading electron densities over a greater area. Spreading electrons also creates charge distribution, therefore, electron-nuclei attraction decreases.
Hence, option $C$ is correct.

Suggest Corrections

Similar questions

Q. Delocalization of electrons increase molecular stability because:

Q. Assertion :Atomic size decreases across period but increases down a group of the periodic table. Reason: Moving from left to right across a period, electrons are added one at a time to the outer energy shell. Electrons within a shell cannot shield each other from the attraction to protons, while moving down a group in the periodic table, the number of electrons and filled electron shells increases.

Using Bohr’s theory in a one-electron atom. Choose the correct option(s). $(n \to$ principal quantum number, z is number of protons in the nucleus).

Q. Assertion (A) : Benzene does not decolourize

B r_{2}

water.
Reason (R) : Benzene is stabilized by resonance due to delocalization of

π

-electrons.

A neutral hydrogen molecule has two protons and two electrons. If one of the electrons is removed we get a hydrogen molecular ion $(H_{2}^{+})$ . In the ground state of $H_{2}^{+}$ the two protons are separated by roughly $1.5$ $A^{o}$ and the electrons is roughly $1$ $A^{o}$ from each proton. The potential energy of the system is :

Join BYJU'S Learning Program