Δ1=∣∣
∣∣xbbaxbaax∣∣
∣∣ and Δ2=∣∣∣xbax∣∣∣ are the given determinants, then
A
Δ1=3(Δ2)2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
ddx(Δ1)=3Δ2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
ddx(Δ1)=3(Δ2)2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Δ1=3(Δ2)3/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Bddx(Δ1)=3Δ2 Δ1=∣∣
∣∣xbbaxbaax∣∣
∣∣=x(x2−ab)−b(ax−ab)+b(a2−ax) ⇒Δ1=x3−3abx+ab2+a2b ⇒ddxΔ1=3(x2−ab)...(1)
Now, Δ2=∣∣∣xbax∣∣∣=x2−ab...(2)
From equation (1) and (2) ddxΔ1=3Δ2