ΔABC and
ΔDBC are two isosceles triangle on the same base
BC and vertices
A and
D are on the same side of
BC (see fig
7.39). If
AD is extended to intersect
BC at
P, show that
(i)
ΔABD≅ΔACD (ii)
ΔABP≅ΔACP(ii)
AP bisects
∠A as wll as
∠D.
(Iv)
AP is the perpendicular bisector of
BC.
![1089815_c77c86b9ee0a44dcb8c2f91dbc8a2f4f.png](https://search-static.byjusweb.com/question-images/toppr_invalid/questions/1089815_c77c86b9ee0a44dcb8c2f91dbc8a2f4f.png)