The correct option is B 22 cm
Given:
ΔABC and ΔPQR are similar triangles. AB = 4 cm, BC = 5 cm, AC = 2 cm, and PQ = 8 cm
We know that corresponding sides of similar triangles are proportional.
∴ PQAB=QRBC=PRAC
84=QR5=PR2
So, QR = 10 cm and PR = 4 cm
Perimeter of ΔPQR = PQ + QR + PR
Perimeter of ΔPQR = 8 + 10 + 4 = 22 cm