Question

$\Delta ABC$ and $\Delta PQR$ are similar triangles such that $\angle A={32}^0$ and $\angle R={65}^{\circ }$, then the value of $\angle B$ is

• A. ${83}^{\circ }$
• B. ${32}^{\circ }$
• C. ${65}^{\circ }$
• D. ${97}^{\circ }$

Answer 1

The correct option is A ${83}^{\circ }$

$△ABC\cong △PQR\therefore \angle C=\angle R\Rightarrow \angle C={65}^{\circ }$

Now in $△ABC$

$\angle A+\angle B+\angle C={180}^{\circ }{32}^{\circ }+\angle B+{65}^{\circ }={180}^{\circ }\Rightarrow \angle B={83}^{\circ }$