$Δ A B C$ , if $A B = 5 c m, B C = 3 c m, C A = 4 c m$ then largest angle is ______

A - -

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B - -

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C - -

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None of these

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Solution

The correct option is C $C - -$
We have use Cosine Formula
$cosA = \frac{b^{2}+c^{2}-a^{}2}{2bc}$
for using this formula, In standard triangle we consider the
AB = c = 5cm
BC = a = 3cm
CA= b = 4cm
when we put these values in formula we will get
$cosA = \frac{4}{5}$
Similarly we will use the formula
$cosB = \frac{a^{2}+c^{2}-b^{}2}{2ac}$ & $cosC = \frac{a^{2}+b^{2}-c^{}2}{2ab}$
& will get the values
$cosB=\frac{3}{5}$ & $cosC=0$
from above we can get to know that the value of cosC is minimum
therefore
the value of angle C will be maximum.

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ΔABC, if AB=5cm,BC=3cm,CA=4cm then largest angle is ______

$Δ A B C$ , if $A B = 5 c m, B C = 3 c m, C A = 4 c m$ then largest angle is ______