Question

$\Delta$ABC in which $\angle$A$={90}^o$ & AB$=$AC then find other angles.

Answer 1

Since $AB=AC$

$\Delta ABC$ is an isoceles triangle

Hence $\angle ABC=\angle ACB$

or $\angle B=\angle C$

$\therefore$ $\angle B=\angle C=x$

$\therefore$ $x+x+{90}^0={180}^0$ $(\angle A+\angle B+\angle C={180}^0)$

$\Rightarrow 2x+{90}^0={180}^0$

$\Rightarrow 2x={90}^0$

$\therefore$ $x={45}^0$