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Question

ΔABC is an isosceles triangle with AB = AC = 13 cm. The length of altitude from A on BC is 5 cm. Find BC.


Solution

In ABC  sides AB=  13cm , AC=13cm

 let M be a point on side BC

Such that BM = a ,MC = a 

AMC is a right angle triangle at M...

By pythagoras theorem 

AM2+MC2=AC2

52+a2=132

a2=16925=144

a2=144

a=12

BC = AM + MC = a + a = 12 + 12 = 24

BC = 24


 

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