Question

$\Delta ABC$ is an obtuse triangle and $AC=6$ units and $CP=3$ units, then the area of $\Delta ABC=$.

• A. $12$ sq. units
• B. $24$ sq. units
• C. $12$ sq. units

Answer 1

The correct option is A $12$ sq. units


Given $\Delta ABC$, we have $AC=6$ units and $BC=5$ units.
$BP$ is the height for the base $AC$.
Now, we know area of a triangle $=\frac{1}{2}\times \text{base}\times \text{height}$
Now, here base $AC=6$ units and height $BP=4$ units
$\therefore$ Area of $\Delta ABC$
$=\frac{1}{2}\times 6\times 4$
$=12$ sq. units