- ABC is right angled at C- Then B - AB - BCA- TrueB- False

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Horizontal Level and Line of Sight

Δ ABC is righ...

Question

$Δ A B C$ is right angled at C. Then $s e c B = \frac{A B}{B C}$

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
True

The secant of an angle is the ratio of the length of the hypotenuse to the length of the adjacent side.

$Δ A B C$ with the right angle at C is the one shown in the figure,

$s e c B = \frac{Hypotenuse}{Adjacent side} = \frac{A B}{B C}$

Suggest Corrections

Similar questions

In a $Δ$ ABC, it is given that AB = AC and AD is drawn perpendicular to BC. D is not the mid-point of BC.

In the above figure, $\frac{1}{2} (∠ B C A) = (\frac{1}{2} ∠ B A Z)$

In $Δ A B C, A B = B C = 6 c m$ . If a circle is drawn with center at B and radius 2 cm which intersects AB and BC at E and D, then $Δ A B C \sim Δ E B D$ .

Q. A right angled

Δ A B C

right angled at B, and

A B = \frac{b}{a}, B C = \frac{a}{b}, ∠ C = θ

then

a sin θ . b cos θ

is:

In a triangle ABC, right angled at B, tan A is equal to the ratio of AB and AC

Join BYJU'S Learning Program

ΔABC is right angled at C. Then secB=ABBC

The correct option is A True The secant of an angle is the ratio of the length of the hypotenuse to the length of the adjacent side. ΔABC with the right angle at C is the one shown in the figure, secB=HypotenuseAdjacent side=ABBC

$Δ A B C$ is right angled at C. Then $s e c B = \frac{A B}{B C}$

The correct option is A
True

The secant of an angle is the ratio of the length of the hypotenuse to the length of the adjacent side.

$Δ A B C$ with the right angle at C is the one shown in the figure,

$s e c B = \frac{Hypotenuse}{Adjacent side} = \frac{A B}{B C}$