- ABC- PQR and -area - ABCarea - PQR-169 If PQ-18 cm and BC-12 cm- then AB and QR are respectively-

The correct option is A 24 cm, 9 cm 169=(ABPQ)^2=(BCQR)^2 ⇒ #160;169=(AB18)^2 and 169=(12QR)^2 ⇒43=AB18 and 43=12Q ⇒ AB=24 cm, ...

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Standard XII

Mathematics

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Δ ABC∼Δ PQR a...

Question

$Δ A B C \sim Δ P Q R$ and $\cdot \frac{a r e a Δ A B C}{a r e a Δ P Q R} = \frac{16}{9}$ If $P Q = 18 c m$ and $B C = 12 c m$ , then AB and QR are respectively.

9 cm, 24 cm

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24 cm, 9 cm

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32 cm, 6.75 cm

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13.5 cm, 16 cm

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Solution

The correct option is A 24 cm, 9 cm
$\frac{16}{9} = (\frac{A B}{P Q})^{2} = (\frac{B C}{Q R})^{2}$
$\Rightarrow \frac{16}{9} = (\frac{A B}{18})^{2}$ and $\frac{16}{9} = (\frac{12}{Q R})^{2}$
$\Rightarrow \frac{4}{3} = \frac{A B}{18}$ and $\frac{4}{3} = \frac{12}{Q}$
$\Rightarrow A B = 24 c m, Q R = 9 c m$

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ΔABC∼ΔPQR and ⋅areaΔABCareaΔPQR=169 If PQ=18cm and BC=12cm, then AB and QR are respectively.

The correct option is A 24 cm, 9 cm169=(ABPQ)2=(BCQR)2⇒169=(AB18)2 and 169=(12QR)2⇒43=AB18 and 43=12Q⇒AB=24cm,QR=9cm

$Δ A B C \sim Δ P Q R$ and $\cdot \frac{a r e a Δ A B C}{a r e a Δ P Q R} = \frac{16}{9}$ If $P Q = 18 c m$ and $B C = 12 c m$ , then AB and QR are respectively.