- ABC - PQR and A - ABC-A - PQR-169- If PQ-18 cm and BC-12 cm- then AB and QR are respectively-

The correct option is B 24 cm, 9 cm 16/9=[AB/PQ]^2=[BC/QR]^2 ⇒16/9=[AB/18]^2 and 16/9=[12/QR]^2 ⇒4/3=AB/18 and 4/3=12/QR ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Relation between Areas and Sides of Similar Triangles

Δ ABC ∼Δ PQR ...

Question

$Δ A B C \sim Δ P Q R$ and $\frac{A (Δ A B C)}{A (Δ P Q R)} = \frac{16}{9}$ . If $P Q = 18$ cm and $B C = 12$ cm, then $A B$ and $Q R$ are respectively:

9

cm,

24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24

cm,

9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

32

cm,

6.75

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13.5

cm,

16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $24$ cm, $9$ cm
$\frac{16}{9} = {[\frac{A B}{P Q}]}^{2} = {[\frac{B C}{Q R}]}^{2}$
$\Rightarrow \frac{16}{9} = {[\frac{A B}{18}]}^{2}$ and $\frac{16}{9} = {[\frac{12}{Q R}]}^{2}$
$\Rightarrow \frac{4}{3} = \frac{A B}{18}$ and $\frac{4}{3} = \frac{12}{Q R}$
$\Rightarrow A B = 24$ cm, $Q R = 9$ cm.

Suggest Corrections

Similar questions

Δ A B C \sim Δ P Q R

and

\frac{a r e a Δ A B C}{a r e a Δ P Q R} = \frac{16}{9}

. If PQ=18 cm and BC=12cm, then AB and QR are respectively

Δ A B C \sim Δ P Q R

and

A (Δ A B C) = 144 c m^{2}

and

A (Δ P Q R) = 100 c m^{2}

. If BC = 12 cm, then find the value of QR.

In the given figure, AB and DE are perpendiculars to BC. If AB = 9cm, DE = 3cm and AC = 24cm then AD is equal to

$I n t h e g i v e n f i g u r e . A B a n d D E a r e p e r p e n d i c u l a r s t o B C . I f A B = 9 c m . D E = 3 c m a n d A C = 24 c m, c a l c u l a t e A D .$

In the above figure, AB = 7 cm & BC = 9 cm. Find the length of CD.

Join BYJU'S Learning Program

ΔABC∼ΔPQR and A(ΔABC)A(ΔPQR)=169. If PQ=18 cm and BC=12 cm, then AB and QR are respectively:

The correct option is B 24 cm, 9 cm169=[ABPQ]2=[BCQR]2⇒169=[AB18]2 and 169=[12QR]2⇒43=AB18 and 43=12QR⇒AB=24 cm, QR=9 cm.

$Δ A B C \sim Δ P Q R$ and $\frac{A (Δ A B C)}{A (Δ P Q R)} = \frac{16}{9}$ . If $P Q = 18$ cm and $B C = 12$ cm, then $A B$ and $Q R$ are respectively: