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Byju's Answer
Standard X
Mathematics
Reducing a Triangle to Two Right Angled Triangles
Δ ABC ∼Δ PQR ...
Question
Δ
A
B
C
∼
Δ
P
Q
R
and
A
B
P
Q
=
2
. Then
A
C
P
R
=
A
2
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B
1
2
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C
1
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Solution
The correct option is
A
2
Given
Δ
A
B
C
∼
Δ
P
Q
R
.
Therefore
A
B
P
Q
=
B
C
Q
R
=
A
C
P
R
and
A
B
P
Q
=
2
So,
A
C
P
R
=
2
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0
Similar questions
Q.
Δ
A
B
C
∼
Δ
P
Q
R
and
A
B
P
Q
=
2
. Then
A
C
P
R
=
Q.
Δ
A
B
C
∼
Δ
P
Q
R
and
A
B
P
Q
=
2
. Then
A
C
P
R
=
Q.
In
Δ
A
B
C
,
A
B
=
5
,
B
C
=
6
,
A
C
=
7
,
Δ
P
Q
R
−
Δ
A
B
C
. Perimeter of
Δ
P
Q
R
is
360
. Find PQ, QR and PR.
Q.
In
Δ
ABC and
Δ
PQR, AB = 4 cm, BC = 5 cm, AC = 6 cm and PQ = 4 cm, QR = 5 cm, PR = 6 cm, then
Q.
Match the column.
1. In
Δ
A
B
C
and
Δ
P
Q
R
,
A
B
P
Q
=
A
C
P
R
,
∠
A
=
∠
P
(a) AA similarity criterion
2. In
Δ
A
B
C
and
Δ
P
Q
R
,
∠
A
=
∠
P
,
∠
B
=
∠
Q
(b) SAS similarity criterion
3. In
Δ
A
B
C
and
Δ
P
Q
R
,
A
B
P
Q
=
A
C
P
R
=
B
C
Q
R
∠
A
=
∠
P
(c) SSS similarity criterion
4. In
Δ
A
C
B
,
D
E
|
|
B
C
⇒
A
D
B
D
=
A
E
C
E
(d) BPT
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