- ABC - PQR and AB-PQ -2- Then AC-PR -

Given Δ ABC ∼Δ PQR. Therefore AB/PQ= BC/QR = AC/PR and AB/PQ = 2 So, AC/PR = 2 ...

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Reducing a Triangle to Two Right Angled Triangles

Δ ABC ∼Δ PQR ...

Question

$Δ A B C \sim Δ P Q R$ and $\frac{A B}{P Q} = 2$ . Then $\frac{A C}{P R} =$

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\frac{1}{2}

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Solution

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Similar questions

Δ A B C \sim Δ P Q R

\frac{A B}{P Q} = 2

\frac{A C}{P R} =

Δ A B C \sim Δ P Q R

\frac{A B}{P Q} = 2

\frac{A C}{P R} =

Δ A B C

A B = 5

B C = 6

A C = 7

Δ P Q R - Δ A B C

Δ P Q R

360

Δ

Δ

1. In $Δ A B C$ and $Δ P Q R$ , $\frac{A B}{P Q} = \frac{A C}{P R}, ∠ A = ∠ P$	(a) AA similarity criterion
2. In $Δ A B C$ and $Δ P Q R$ , $∠ A = ∠ P, ∠ B = ∠ Q$	(b) SAS similarity criterion
3. In $Δ A B C$ and $Δ P Q R$ , $\frac{A B}{P Q} = \frac{A C}{P R} = \frac{B C}{Q R}$ $∠ A = ∠ P$	(c) SSS similarity criterion
4. In $Δ A C B, D E \| \| B C$ $\Rightarrow \frac{A D}{B D} = \frac{A E}{C E}$	(d) BPT

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