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Byju's Answer
Standard VIII
Mathematics
Rectangle
Δ ABC ∼Δ PQR....
Question
Δ
A
B
C
∼
Δ
P
Q
R
. If
A
B
P
Q
=
1
2
, then find the value of
B
C
Q
R
.
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Solution
Given,
Δ
A
B
C
∼
Δ
P
Q
R
∴
A
B
P
Q
=
B
C
Q
R
=
A
C
P
R
=
1
2
∴
B
C
Q
R
=
1
2
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0
Similar questions
Q.
If in two triangles
Δ
A
B
C
and
Δ
P
Q
R
,
A
B
=
Q
R
,
B
C
=
P
R
and
C
A
=
P
Q
,
then :
Q.
In
Δ
A
B
C
,
A
B
=
5
,
B
C
=
6
,
A
C
=
7
,
Δ
P
Q
R
−
Δ
A
B
C
. Perimeter of
Δ
P
Q
R
is
360
. Find PQ, QR and PR.
Q.
Δ
A
B
C
∼
Δ
P
Q
R
and
⋅
a
r
e
a
Δ
A
B
C
a
r
e
a
Δ
P
Q
R
=
16
9
If
P
Q
=
18
c
m
and
B
C
=
12
c
m
, then AB and QR are respectively.
Q.
Question 4
If in two triangles
Δ
A
B
C
a
n
d
Δ
P
Q
R
,
A
B
Q
R
=
B
C
P
R
=
C
A
P
Q
, then
(A)
Δ
P
Q
R
∼
Δ
C
A
B
(B)
Δ
P
Q
R
∼
Δ
A
B
C
(C)
Δ
C
B
A
∼
Δ
P
Q
R
(D)
Δ
B
C
A
∼
Δ
P
Q
R
Q.
Question 4
If in two and
Δ
A
B
C
a
n
d
Δ
P
Q
R
,
A
B
Q
R
=
B
C
P
R
=
C
A
P
Q
, then
(A)
Δ
P
Q
R
∼
Δ
C
A
B
(B)
Δ
P
Q
R
∼
Δ
A
B
C
(C)
Δ
C
B
A
∼
Δ
P
Q
R
(D)
Δ
B
C
A
∼
Δ
P
Q
R
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