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Byju's Answer
Standard X
Mathematics
Basic Proportionality Theorem
Δ ABC ∼Δ PQR ...
Question
Δ
A
B
C
∼
Δ
P
Q
R
and
A
B
P
Q
=
2.
Find the value of
A
C
P
R
.
2
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Solution
The correct option is
A
2
Given:
Δ
A
B
C
∼
Δ
P
Q
R
A
B
P
Q
=
2
Since the triangles are similar, the corresponding sides are proportional.
∴
A
B
P
Q
=
B
C
Q
R
=
A
C
P
R
a
n
d
A
B
P
Q
=
2.
So,
A
C
P
R
=
2
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Similar questions
Q.
Δ
A
B
C
∼
Δ
P
Q
R
and
A
B
P
Q
=
2
. Then
A
C
P
R
=
Q.
Δ
A
B
C
∼
Δ
P
Q
R
and
A
B
P
Q
=
2
. Then
A
C
P
R
=
Q.
In
Δ
A
B
C
,
A
B
=
5
,
B
C
=
6
,
A
C
=
7
,
Δ
P
Q
R
−
Δ
A
B
C
. Perimeter of
Δ
P
Q
R
is
360
. Find PQ, QR and PR.
Q.
In
Δ
ABC and
Δ
PQR, AB = 4 cm, BC = 5 cm, AC = 6 cm and PQ = 4 cm, QR = 5 cm, PR = 6 cm, then
Q.
Δ
A
B
C
∼
Δ
P
Q
R
. If
A
B
P
Q
=
1
2
, then find the value of
B
C
Q
R
.
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