- ABC - PQR- If BC - 14 cm andAB-PQ - 2- then QR - cm-

Given, Δ ABC ∼Δ PQR. So ratio of their corresponding sides are equal. ∴AB/PQ = BC/QR = AC/PR Given, AB/PQ = 2 ∴BC/QR = 2 ⇒14/QR=2 ⇒ QR = 14/2 ⇒ QR = 7 cm ...

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Byju's Answer

Standard IX

Mathematics

Similar Triangles

Δ ABC ∼Δ PQR,...

Question

$Δ A B C \sim Δ P Q R, If BC = 14 cm and$
$\frac{A B}{P Q} = 2, then QR =$ cm.

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Solution

The correct option is C 7
Given, $Δ A B C \sim Δ P Q R$ . So ratio of their corresponding sides are equal.
$∴ \frac{A B}{P Q} = \frac{B C}{Q R} = \frac{A C}{P R}$
Given, $\frac{A B}{P Q} = 2$
$∴ \frac{B C}{Q R} = 2$
$\Rightarrow \frac{14}{Q R} = 2$
$\Rightarrow Q R = \frac{14}{2}$
$\Rightarrow Q R = 7 c m$

Suggest Corrections

Similar questions

Δ A B C \sim Δ P Q R, If BC = 14 cm and

\frac{A B}{P Q} = 2, then QR =

cm.

Q. CM and RN are respectively the medians of

Δ A B C

and

Δ P Q R

. If

Δ A B C \sim Δ P Q R

, prove that:

(A)

Δ A M C \sim Δ P N R

(B)

\frac{C M}{R N} = \frac{A B}{P Q}

Δ

ABC and

Δ

Δ

PQR.

Δ A B C \sim Δ P Q R

and

\frac{A B}{P Q} = 2

. Then

\frac{A C}{P R} =

If Δ A B C is similar to Δ P Q R

such that 2 A B = P Q and B C = 6 c m, then QR is equal to:

[1 Mark]

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ΔABC∼ΔPQR,If BC = 14 cm and ABPQ=2,then QR = cm.

The correct option is C 7Given, ΔABC∼ΔPQR. So ratio of their corresponding sides are equal. ∴ABPQ=BCQR=ACPR Given, ABPQ=2 ∴BCQR=2 ⇒14QR=2 ⇒QR=142 ⇒QR=7 cm

$Δ A B C \sim Δ P Q R, If BC = 14 cm and$
$\frac{A B}{P Q} = 2, then QR =$ cm.