$Δ A M C ≅ Δ A N B$
If the above statement is true then mention answer as 1, else mention 0 if false

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Solution

$A B = A C$ (Given)
$B M = N C$ (Given)
Subtracting both the equations:
$A B - B M = A C - N C$
$A M = A N$
Now, in $△$ s, ABN and ACM,
$A B = A C$ (given)
$A M = A N$ (Proved above)
$∠ A = ∠ A$ (Common)
Thus, $△ A B N ≅ △ A C M$ (SAS congruency)

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