Question

$\Delta AMT\sim \Delta AHE$. In $\Delta AMT$, $MA=6.3cm$, $\angle MAT={120}^o$, $AT=4.9cm$, $\frac{MA}{HA}=\frac{7}{5}$ Construct $\Delta AHE$.

Answer 1

$\angle MAT=120°$

$\frac{MA}{HA}=\frac{7}{5}\Rightarrow HA=\frac{5}{7}MA$ $=\frac{5}{7}\times 6.3$ $=4.5$

Similarly as they are similar triangles.

$\frac{AT}{AE}=\frac{7}{5}\Rightarrow AE=\frac{5}{7}AT$

$=\frac{5}{7}\times 4.9$ $=3.5$

For constructing $△AHE$

Draw a line $AH=4.5cm$

Draw a line $120°$ with $AH$.

Mark $E$ on the line such that $AE=3.5$

Join $E,H$

Then $△AHE$ is complete.