Question

$\Delta APB$ is similar to $\Delta CPD$.

Enter 1 if true , else 0

Answer 1

Given: ABCD is a trapezium with $AB\parallel CD$
In $△APB$ and $△CPD$,
$\angle APB=\angle CPD$ (Vertically opposite angles)
$\angle PAB=\angle PCD$ (Alternate angles)
$\angle PBA=\angle PDC$ (Alternate angles)
Thus, $△APB\sim △CPD$ (AAA rule)