$Δ C_{p}$ for change $N_{2} (g) + 3 H_{2} (g) = 2 N H_{3} (g)$ is:

C_{p N H_{3}} - (C_{p N_{2}})

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2 C_{p N H_{3}} - (C_{p N_{2}} + 3 C_{p H_{2}})

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2 C_{p N H_{3}} - (C_{p H_{2}})

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2 C_{p N H_{3}} + (C_{p N_{2}} + 3 C_{p H_{2}})

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Solution

The correct option is D $2 C_{p N H_{3}} - (C_{p N_{2}} + 3 C_{p H_{2}})$
$Δ C_{p}$ represents the change in the heat capacity at constant pressure. It is equal to the difference in the heat capacities of the products and the reactants.
$Δ C_{p} = C_{p} o f p r o d u c t s - C_{p} o f r e a c t a n t s$ .
$Δ C_{p}$ for change $N_{2} (g) + 3 H_{2} (g) = 2 N H_{3} (g)$ is given by the following expression.
$Δ C_{p} = 2 C_{p N H_{3}} - (C_{p N_{2}} + 3 C_{p H_{2}})$

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Similar questions

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H

△ U

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

k

2 N H_{3} (g) ⇌ N_{2} (g) + 3 H_{2} (g)

For $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g) + h e a t$

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g),

t = 40 s e c

N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g); Δ H = - 22 k c a l

E_{a}

70 k c a l

2 N H_{3} (g) \to N_{2} (g) + 3 H_{2} (g)

k c a l

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