The correct option is C 14 cm
Given: ΔDEF ∼ ΔPQR, ratio of corresponding sides = 2 : 1
So, DEPQ=EFQR=DFPR=21
DE = 2PQ, EF = 2QR, and DF = 2PR
Perimeter of ΔDEF = DE + EF + DF
28 = 2PQ + 2QR + 2PR
28 = 2(PQ + QR + PR)
28 = 2(Perimeter of ΔPQR)
Perimeter of ΔPQR = 14 cm