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Question

ΔfGo for NH4OH(aq)NH+4(aq)+OH(aq) is about:

A
27.07kJ mol1
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B
54.14kJ mol1
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C
27.07kJ mol1
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D
54.14kJ mol1
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Solution

The correct option is B 27.07kJ mol1
Kb=1.8×105
ΔfGorxn for NH4OH(aq)NH+4(aq)+OH(aq)
=2.303×R×TlogKb
=2.303×8.314×298log(1.8×105)
=27.07 kJ mol1

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