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Question

ΔG=77.77kJmol1 at 1000K for the reaction 12N2(g)+12O2(g)=NO(g). Partial pressure of NO under equilibrium at 1000K for air at 1 atm pressure containing 80% N2 and 20% O2 by volume is X×105 atm. 100X is__________.

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Solution

ΔGo=RTlnK
77770=8.314×1000×lnK
lnK=9.354
K=8.66×105

N2
O2 NO
Initial moles
0.8
0.2
0
Moles at eqm
0.8y 0.2y 2y

2y(0.8y)0.5(0.2y)0.5=8.66×105

4y2(0.8y)(0.2y)=7.5×109

y=6.85×106

2y=1.37×105=X×105

X=1.37

100X=137

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