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Relation between Kp and Kc

Δ Go 298 K fo...

Question

$Δ G^{o} (298 K)$ for the reaction $\frac{1}{2} N_{2} + \frac{3}{2} H_{2}_{1} N H_{3}$ is -16.5 kJ $m o l^{- 1}$ . The equilibrium constant $(K_{1})$ at $25^{o} C$ & the equilibrium constant $K_{2}$ and $K_{3}$ for the following reactions are
$N_{2} + 3 H_{2}_{2} 2 N H_{3}$
$N H_{3}_{3} \frac{1}{2} N_{2} + \frac{3}{2} H_{2}$

A

K_{1} = 779.4, K_{2} = 6.074 \times 10^{5}; K_{3} = 1.283 \times 10^{- 3}

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B

K_{1} = 779.4, K_{2} = 2.183 \times 10^{5}; K_{3} = 3.576 \times 10^{3}

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C

K_{1} = 124.4, K_{2} = 6.074 \times 10^{5}; K_{3} = 2.34 \times 10^{3}

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D

N o n e o f t h e s e

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Solution

The correct option is C $K_{1} = 779.4, K_{2} = 6.074 \times 10^{5}; K_{3} = 1.283 \times 10^{- 3}$
$Δ G^{o} = - R T l n K_{1}$
$- 16500 = - 8.314 \times 298 \times l n K_{1}$
$6.6597 = l n K_{1}$
$K_{1} = 779.4$
$K_{2} = K_{1}^{2} = (779.4)^{2} = 6.074 \times 10^{5}$
$K_{3} = \frac{1}{K_{1}} = \frac{1}{779.4} = 1.283 \times 10^{- 3}$

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Similar questions

25^{o}

C, the equilibrium constants

K_{1}, K_{2}

K_{3}

of three reactions are:

N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}

N_{2} + O_{2} ⇌ 2 N O; K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O; K_{3}

The equilibrium constants for the oxidation of

N H_{3}

by oxygen to given

N O

Q. The following equilibrium are given

N_{2} + 3 H_{2} ⇌ 2 N H_{3}

K_{1}

N_{2} + O_{2} ⇌ 2 N O

---------------

K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O

---------------

K_{3}

The equilibrium constant of the reaction

2 N H_{3} + \frac{5}{2} O_{2} ⇌ 2 N O + 3 H_{2} O

K_{1}, K_{2}

K_{3}

Q. The following equilibrium are given

N_{2} + 3 H_{2} \to 2 N H_{3} - K_{1}

N_{2} + O_{2} \to 2 N O - K_{2}

H_{2} + 1 / 2 O_{2} \to H_{2} O - K_{3}

The equilibrium constant of reaction,

3 H_{2} + 5 / 2 O_{2} \to 2 N O + 3 H_{2} O

K_{1}, K_{2}, K_{3}

Q. For the reaction,

2 N H_{3} \to N_{2} + 3 H_{2}

- \frac{Δ [N H_{3}]}{Δ t} = K_{1} [N H_{3}]; \frac{Δ [N_{2}]}{Δ t} = K_{2} [N H_{3}]; \frac{Δ [H_{2}]}{Δ t} = K_{3} [N H_{3}]

Then relation between

k_{1}, k_{2}

k_{3}

Q. The following equilibrium are given:

N_{2} + 3 H_{2} ⇌ 2 {N H}_{3}

K_{1}

N_{2} + O_{2} ⇌ 2 N O

K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O

K_{3}

The equilibrium constant of the reaction

2 {N H}_{3} + \frac{5}{2} O_{2} ⇌ 2 N O + 3 H_{2} O

K_{1}, K_{2}

K_{3}

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