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Molarity

Δ G⊖ standard...

Question

$Δ G^{⊖}$ (standard free energy change) is free energy change for the process at what temperature of when reactants react completely to form products.(in K)

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Solution

The free-energy change $Δ G^{⊖}$ for a reaction occurring under a set of standard conditions: temperature, 298 K; pressure, 1 atm or 101.3 kPa; and all solutes at 1 M concentration.

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Similar questions

Δ G^{⊖}

Δ G = Δ G^{\circ} + R T l n Q_{P}

Δ G = 0 and Q_{p} = K_{P}

Δ G^{\circ} = - R T l n K_{P}

K represents K_{P}

1 M or 1 atm

Δ G^{\circ} = - v e or K > 1 : forward reaction is feasible

Δ G^{\circ} = + v e or K < 1 : reverse reaction is feasible

Δ G^{\circ} = 0 or K = 1 : reaction is at equilibrium (very rare)

K_{c}

N_{2} O_{4} ⇌ 2 N O_{2}

291 K

1.14

0.5 {mol dm}^{- 3}

R = 0.082 {lit atm K}^{- 1} {mol}^{- 1}

(Δ G)

(Δ S)

(T)

(Δ G)

100^{\circ} C

Δ G = Δ G^{\circ} + R T l n Q_{P}

Δ G = 0 and Q_{p} = K_{P}

Δ G^{\circ} = - R T l n K_{P}

K represents K_{P}

1 M or 1 atm

Δ G^{\circ} = - v e or K > 1 : forward reaction is feasible

Δ G^{\circ} = + v e or K < 1 : reverse reaction is feasible

Δ G^{\circ} = 0 or K = 1 : reaction is at equilibrium (very rare)

N i O (s) + C O (g) ⇌ N i (s) + C O_{2} (g), Δ G^{\circ} ({J Mol}^{- 1}) = - 20700 - 11.97 T .

1 atm

400 ppm

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