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Question

ΔG vs T plot in the Ellingham diagram slopes downward for the reaction.

A
Mg+12O2MgO
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B
2Ag+12O2Ag2O
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C
C+12O2CO
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D
CO+12O2CO2
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Solution

The correct option is C C+12O2CO
In Ellingham diagram,
higher is the slope higher is the entropy change so
ΔS(C(s)+1/2O2(g)CO(g))>ΔS(C(S)+O2(g)CO2(g)
as CO have higher slope.
Also,
Carbon monoxide is a more effective reducing agent than carbon below 983 K but above this temperature the reverse is true.

1491013_214995_ans_e47de7c3039343428490ff081798d1ce.png

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