- H- E for the reaction-

Δ H=Δ E+n_gRT,Δ H lt;Δ E if Δ n_g lt;0 Δ n_g=n_P(g) n_R(g) (a) Δ n_g=3 (3+1)= 1 (b) nbsp;Δ n=(12) (0)=0.5 (c) nbsp;Δ n=(1) (12)=0.5 (d) nbsp; nbsp;Δ ...

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Byju's Answer

Standard XII

Chemistry

First Law of Thermodynamics

Δ H<Δ E for t...

Question

$Δ H < Δ E$ for the reaction:

N_{2} (g) + 3 H_{2} (g) \to 3 H_{2} (g)

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A g_{2} O (s) \to 2 A g (s) + 1 / 2 O_{2} (g)

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C (s) + 1 / 2 O_{2} (g) \to C O (g)

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C (s) + O_{2} (g) \to C O_{2} (g)

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Solution

The correct option is A $N_{2} (g) + 3 H_{2} (g) \to 3 H_{2} (g)$
$Δ H = Δ E + n_{g} R T, Δ H < Δ E$ if $Δ n_{g} < 0$
$Δ n_{g} = n_{P} (g) - n_{R} (g)$
(a) $Δ n_{g} = 3 - (3 + 1) = - 1$
(b) $Δ n = (\frac{1}{2}) - (0) = 0.5$
(c) $Δ n = (1) - (\frac{1}{2}) = 0.5$
(d) $Δ n = (1) - (1) = 0$

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Similar questions

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Δ H

and

Δ E

in this reaction?

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N_{2} + 3 H_{2} ⇌ 2 N H_{3}; Δ H =

Q. For which of the following reactions,

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For a particular reaction ;

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= Δ H + P Δ

For which of the following reactions, $Δ H = Δ E + 2 R T$ ?

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ΔH<ΔE for the reaction:

The correct option is A N2(g)+3H2(g)→3H2(g)ΔH=ΔE+ngRT,ΔH<ΔE if Δng<0 Δng=nP(g)−nR(g) (a) Δng=3−(3+1)=−1 (b) Δn=(12)−(0)=0.5 (c) Δn=(1)−(12)=0.5 (d) Δn=(1)−(1)=0

$Δ H < Δ E$ for the reaction:

The correct option is A $N_{2} (g) + 3 H_{2} (g) \to 3 H_{2} (g)$
$Δ H = Δ E + n_{g} R T, Δ H < Δ E$ if $Δ n_{g} < 0$
$Δ n_{g} = n_{P} (g) - n_{R} (g)$
(a) $Δ n_{g} = 3 - (3 + 1) = - 1$
(b) $Δ n = (\frac{1}{2}) - (0) = 0.5$
(c) $Δ n = (1) - (\frac{1}{2}) = 0.5$
(d) $Δ n = (1) - (1) = 0$