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Byju's Answer
Standard XII
Chemistry
Enthalpy
Δ H -Δ U for ...
Question
(
Δ
H
−
Δ
U
)
for the formation of carbon monoxide
(
C
O
)
from its elements at
298
K
is
(
R
=
8.314
J
K
−
1
mol
−
1
)
A
1238.78
J
mol
−
1
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B
−
2477.57
J
mol
−
1
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C
2477.57
J
mol
−
1
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D
−
1238.78
J
mol
−
1
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Solution
The correct option is
A
1238.78
J
mol
−
1
Δ
H
−
Δ
U
=
Δ
n
g
R
T
C
(
s
)
+
1
2
O
2
(
g
)
→
C
O
(
g
)
Δ
n
g
=
1
−
1
2
=
+
1
2
Δ
H
−
Δ
U
=
1
2
×
8.314
×
298
=
1238.78
J
mol
−
1
Suggest Corrections
0
Similar questions
Q.
(
Δ
H
−
Δ
U
)
for the formation of carbon monoxide
(
C
O
)
from its element at
298
K
is:
(
R
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8.314
J
K
−
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o
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−
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)
Q.
The value of
(
Δ
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the formation of carbon monoxide from its elements at
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(
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H
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U
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for the formation of carbon monoxide
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from its elements at
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(
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H
−
Δ
U
)
in J/mol for the formation of carbon monoxide
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C
O
)
from its elements at
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=
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Q.
d
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Δ
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Calculate
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