- H - U for the formation of carbon monoxide CO from its elements at 298 K is R -8-314 J K -1 mol -1A- 1238-78 J mol -1B- -2477-57 J mol -1C- 2477-57 J mol -1D- -1238-78 J mol -1

The correct option is A 1238.78 J mol 1 C(s) + 1/2O_2(g) → CO Δ H = Δ U + Δ nRT or Δ H Δ U = Δ nRT; Δ n = 1 1/2 = 1/2; Δ H Δ U = 1/2 × 8.314 × 298 = 12 ...

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Standard XII

Chemistry

Difference between Internal Energy and Enthalpy

Δ H -Δ U for ...

Question

$(Δ H - Δ U)$ for the formation of carbon monoxide ( $C O$ ) from its elements at $298 K$ is ( $R = 8.314 J K^{- 1} m o l^{- 1}$ )

−2477.57 J mol^-1

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2477.57 J mol^-1

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−1238.78 J mol^-1

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1238.78 J mol^-1

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Solution

The correct option is D
1238.78 J mol^-1

$C (s) + \frac{1}{2} O_{2} (g) \to C O$

$Δ H = Δ U + Δ n R T$ or $Δ H - Δ U = Δ n R T$ ;

$Δ n = 1 - \frac{1}{2} = \frac{1}{2}; Δ H - Δ U = \frac{1}{2} \times 8.314 \times 298$

= $1238.78 J m o l^{- 1}$

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Similar questions

(Δ H - Δ U)

for the formation of carbon monoxide

(C O)

from its element at

298 K

is:

(R = 8.314 J K^{- 1} {m o l}^{- 1})

Q. The value of

(Δ H - Δ U)

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298 K

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(Δ H - Δ U)

for the formation of carbon monoxide

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from its elements at

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(R = 8.314 J K^{- 1} {mol}^{- 1})

(Δ H - Δ U)

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from its elements at

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for the following reaction at

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(ΔH − ΔU) for the formation of carbon monoxide (CO) from its elements at 298 K is ( R = 8.314 J K−1 mol−1)

The correct option is D 1238.78 J mol-1 C(s) + 12O2(g) → CO ΔH = ΔU + ΔnRT or ΔH − ΔU = ΔnRT; Δn = 1 − 12 = 12;ΔH − ΔU = 12 × 8.314 × 298 = 1238.78 J mol−1

$(Δ H - Δ U)$ for the formation of carbon monoxide ( $C O$ ) from its elements at $298 K$ is ( $R = 8.314 J K^{- 1} m o l^{- 1}$ )

The correct option is D
1238.78 J mol^-1

$C (s) + \frac{1}{2} O_{2} (g) \to C O$

$Δ H = Δ U + Δ n R T$ or $Δ H - Δ U = Δ n R T$ ;

$Δ n = 1 - \frac{1}{2} = \frac{1}{2}; Δ H - Δ U = \frac{1}{2} \times 8.314 \times 298$

= $1238.78 J m o l^{- 1}$