ΔHof for NF3−113kJ/mol. Bond energy for N−F bond is 27.5kJ/mol. Calculate the bond energies of N2 and F2 if their magnitudes are in the ratio 6:1 are, respectively
A
822.5,137.1kJ/mol
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B
979.8,163.3kJ/mol
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C
949.32,157.22kJ/mol
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D
762.6,127.1kJ/mol
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Solution
The correct option is C949.32,157.22kJ/mol 12N2+32F2→Nf3