$Δ H_{v a p} = 30 k J / m o l$ and $Δ S_{v a p} = 75 J m o l^{- 1} K^{- 1}$ . Find the temperature of vapour, at one atmosphere.

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Solution

$Δ H = T Δ S$
$T = \frac{Δ H}{Δ S} = \frac{30, 000}{75} = 400 K$

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Similar questions

Δ H_{v a p} = 30 k J / m o l e

Δ S_{v a p} = 75

^{- 1} K^{- 1}

Δ H_{v a p} = 30 kJ/mol

Δ S_{v a p} = 75 {J mol}^{- 1} K^{- 1}

Δ H_{v a p} = 40.73 k J m o l^{- 1}

Δ S_{v a p} = 0.109 k J K^{- 1} m o l^{- 1}

Δ H_{v a p} = 40.73 k J {m o l}^{- 1}

Δ S_{v a p} = 0.109 k J {m o l}^{- 1} K^{- 1}

30 k J / m o l

75 J m o l^{- 1} K^{- 1}

1 a t m

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