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Molarity

Density of 2....

Question

Density of 2.05 M solution of acetic acid in water is 1.02 g/ml. Find molality of same solution.

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Solution

Weight of acetic acid : 2.05 $\times$ 60 = 123 g
Weight of solution = 1000 $\times$ 1.02 = 1020 g
Weight of water = 1020 - 123 = 897 g
Molality = $\frac{2.05 \times 1000}{897} = 2.28 m$

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