Density of a concrete slab is 2320 1exkg- -1exm3- What is its relative density- Given that density of water - 1-1031exkg- -1exm3-

Step 1: Given data, 0ex0ex density of water(ρ_w)=1×10^31exkg/ 1exm^3.0ex0ex density of concrete slab(ρ_c)=2320 1exkg/ 1e ...

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Standard IX

Physics

Density

Density of a ...

Question

Density of a concrete slab is $2320 \frac{k g}{m^{3}}$ . What is its relative density? Given that density of water = $1 \times 10^{3} \frac{k g}{m^{3}}$ .

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Solution

$S t e p 1 : - G i v e n d a t a, d e n s i t y o f w a t e r (ρ_{w}) = 1 \times 10^{3} \frac{k g}{m^{3}} d e n s i t y o f c o n c r e t e s l a b (ρ_{c}) = 2320 \frac{k g}{m^{3}} S t e p 2 : - T o f i n d, r e l a t i v e d e n s i t y (ρ) = ? S t e p 3 : - W e k n o w n t h a t, F o r m u l a, R e l a t i v e d e n s i t y (ρ) = \frac{D e n s i t y o f a c o n c r e t e s l a b (ρ_{c})}{D e n s i t y o f a w a t e r (ρ_{w})} \Rightarrow ρ = \frac{2320}{1 \times 10^{3}} \Rightarrow ρ = \frac{2320}{1000} \Rightarrow ρ = 2.32 S t e p 4 : - H e n c e, R e l a t i v e d e n s i t y o f a m a t e r i a l i s 2.32$

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Density of a concrete slab is 2320kgm3. What is its relative density? Given that density of water = 1×103kgm3.

Step1:-Givendata,densityofwater(ρw)=1×103kgm3densityofconcreteslab(ρc)=2320kgm3Step2:-Tofind,relativedensity(ρ)=?Step3:-Weknownthat,Formula,Relativedensity(ρ)=Densityofaconcreteslab(ρc)Densityofawater(ρw)⇒ρ=23201×103⇒ρ=23201000⇒ρ=2.32Step4:-Hence,Relativedensityofamaterialis2.32

Density of a concrete slab is $2320 \frac{k g}{m^{3}}$ . What is its relative density? Given that density of water = $1 \times 10^{3} \frac{k g}{m^{3}}$ .