Density of a gas at 276 $K$ and 380 $m m$ pressure is 1.5 gram/litre. Weight of 1.25 mole of gas in grams is:

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Solution

The correct option is B 85
$d = \frac{P M}{R T}$

$P =$ Pressure $= \frac{380}{760} = 0.5 a t m$
$1.5 = \frac{0.5 \times M}{0.0821 \times 276}$
$M = 68 g m$

Weight of 1 mole of gas $= 68 g m$
Weight of 1.25 moles of gas $= 85 g m$ .

Hence, the correct answer is option $B$ .

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