Question

Density of a material is equal to its mass divided by its volume. What is the density (in $kg{m}^{-3}$) of a rock of mass $1.8kg$ and volume $6\times {10}^{-4}{m}^3$?

Answer 1

Step 1: Given data:
The mass of rock, $M=1.8kg$
The volume of rock, $V=6\times {10}^{-4}{m}^3$
Step 2: Calculate the value of density
$$\begin{gathered} Density=\frac{Mass}{Volume} \\ =\frac{1.8}{6\times {10}^{-4}} \\ =\frac{1.8}{6\times {10}^{-4}} \\ =0.3\times {10}^{4}kg{m}^{-3} \end{gathered}$$
Thus, the density (in $kg{m}^{-3}$) of a rock of mass $1.8kg$ and volume $6\times {10}^{-4}{m}^3$ is $\mathbf{0}\mathbf{.}\mathbf{3}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{4}}\mathbf{}\mathit{k}\mathit{g}{\mathit{m}}^{\mathbf{-}\mathbf{3}}$.