Density of a mercury is $13600 k g m^{- 3}$ . Its relative density is :

$13600$

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$1360$

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$136$

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$13.6$

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Solution

The correct option is D
$13.6$

The ratio between density of a substance and density of water, is called relative density.
$R e l a t i v e D e n s i t y (R . D) o f m e r c u r y = \frac{D e n s i t y o f m e r c u r y}{D e n s i t y o f w a t e r}$
$R . D o f m e r c u r y = \frac{13600 k g m^{- 3}}{1000 k g m^{- 3}} = 13.6$ [ $∵$ $D e n s i t y o f w a t e r = 1000 k g m^{- 3}$ ]
Therefore, relative density of mercury is $13.6$ .
Hence, the correct answer is option (D) i.e. $13.6$

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