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Question

Density of equilibrium mixture of N2O4 and NO2 at 1 atm and 384 K is 1.84 g dm3. Calculate the equilibrium constant of the reaction, N2O4(g)2NO2(g).

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Solution

We know that,

PMmix=dRT
1×Mmix=1.84×0.0821×384
M=29×2
Vapour density (d) at equilibrium =29

Initial vapour density =M/2=92/2=46

x=Dd(n1)d=462929=0.586

N2O4(g)2NO2(g)
t=0 1 0
teq. 1x 2x
Total moles=1+x
pN2O4=(1x)(1+x)×P;pNO2=2x(1+x)×P

Kp=4x2P1x2=4×(0.586)2×11(0.586)2=2.09 atm

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