Question

Density of ice is $\sigma$ and that of water is $\rho$. What will be the decrease in volume when a mass $M$ of ice melts

• A. $\frac{M}{\sigma -\rho }$
• B. $\frac{\sigma -\rho }{M}$
• C. $M[\frac{1}{\sigma }-\frac{1}{\rho }]$
• D. $M[\frac{1}{\rho }-\frac{1}{\sigma }]$

Answer 1

The correct option is D $M[\frac{1}{\rho }-\frac{1}{\sigma }]$

Volume of ice= Mass/Density= $M/P$

Volume of water= Mass/Density= $M/\sigma$

Decrease in volume= $V_i-V_w$

$=\frac{M}{P}-\frac{M}{\sigma }=M[\frac{1}{P}-\frac{1}{\sigma }]$