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Determination of Significant Digits in a Number

Density of ma...

Question

Density of material is 8 g /cc. In a new system in which unit of length is 5 cm and unit of mass is 20 g, density of material in new system will be

A

40

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B

50

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C

24

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D

80

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Solution

The correct option is B 50
In the new system, $1 L = 5 c m$
So, $1 L^{3} = 5^{3} c c$ and $1 c c = 5^{- 3} L^{3}$
$1 M = 20 g$ and $1 g = \frac{1}{20} M$
Therefore, $8 \frac{g}{c c} = 8 \frac{1 / 20}{5^{- 3}} = 50 \frac{M}{L^{3}}$

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