Density of oxygen at NTP is 1.429 g/litre. Calculate the standard molar volume of the gas.

20 l i t r e m o l^{- 1}

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11.39 l i t r e m o l^{- 1}

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22.4 l i t r e m o l^{- 1}

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22 l i t r e m o l^{- 1}

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Solution

The correct option is D $22.4 l i t r e m o l^{- 1}$
Given density of oxygen $= 1.429 g / L$
Molar mass of $O_{2} = 16 \times 2 = 32 g$
Density $= \frac{M a s s}{v o l u m e}$
volume $= \frac{M a s s}{D e n s i t y}$
volume $= 22.39 L [\frac{32}{1.429} = 22.39]$
$≅ 22.4 L$

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