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Variation of G Due to the Rotation of Earth

Derivation fo...

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Derivation for maximum range in both the cases when a particle is thrown upward as well as downward from an inclined plane.

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Q. A particle is projected on an inclined plane with a speed u as shown in Fig. Find the range of the particle on the inclined plane.

Q. An inclined plane makes an angle

θ_{0} = 30^{o}

with the horizontal. A particle is projected from this plane with a speed of

5 m s^{- 1}

at an angle of elevation

β = 30^{o}

with the horizontal as shown in Fig.
a. Find the range of the particle on the plane when it strikes the plane.
b. find the range of the particle for

β = 120

Q. Two balls are thrown from an inclined plane at angle of projection

α

with the plane one up the incline plane and other down the incline as shown in the figure. If

R_{1}

R_{2}

be their respective ranges and

h_{1}

h_{2}

be their respective maximum height then
[here

T_{1}

T_{2}

are times of flight in the two cases respectively]

Q. A particle is projected from the bottom of an inclined plane of inclination

30^{\circ} .

α

(from the horizontal) should the particle be projected to get the maximum range on the inclined plane.

Q. The maximum range of projectile is

500 m

. If the particle is thrown up a plane, which is inclined at an angle of

30^{o}

with the same speed, the distance covered by it along the inclined plane will be:

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Variation of G Due to the Rotation of Earth

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