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Byju's Answer
Standard XII
Physics
Center of Mass as an Average Point
Derivation of...
Question
Derivation of center of mass in quadrant of circle
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Q.
The ends of a quadrant of a circle have the coordinates
(
1
,
3
)
and
(
3
,
1
)
. The center of such a circle is:
Q.
A circle of radius
2
has center at
(
2
,
0
)
. Another circle of radius
1
has center at
(
5
,
0
)
. A line is tangent to the two circles at points in the first quadrant. Which of the following is the y-intercept of the line?
Q.
A circle of radius
2
unit lies in the first quadrant and touches both the axes of coordinates, equation of circle with center at
(
6
,
5
)
and touching the above circle externally is
Q.
Find the equation of circle which touches
x
&
y
axis & perpendicular distance of center of circle from
3
x
+
4
y
+
11
=
0
is
5
. Given circle lies
1
s
t
quadrant
Q.
The equation of the circle of radius
4
and center lies in the first quadrant which touches the x-axis and the line
4
x
−
3
y
=
0
is-
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Standard XII Physics
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