Derivation of second equation of motion is:

d θ = w d 2 t

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d θ = w d t

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d θ = w d 3 t

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d θ = w d t^{2}

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Solution

The correct option is B $d θ = w d t$
$S = u t + \frac{1}{2} a t^{2}$
$θ = w_{0} t + \frac{1}{2} α t^{2}$
$w = \frac{d θ}{d t}$
$d θ = w d t$

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