CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
232
You visited us 232 times! Enjoying our articles? Unlock Full Access!
Question

Derivative of f(x)=x2cosx is

A
2xcosx+x2sinxsinx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2xcosx+x2sinxcosx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2xcosx+x2sinxcos2x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2xcosxx2sinxcos2x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2xcosx+x2sinxcos2x
Given, f(x)=x2cosx
So, derivative of the function is given as
df(x)dx=d(x2cosx)dx
Using Division method we have
cosxdx2dxx2dcosxdx(cosx)2
2xcosx+x2sinxcos2x

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Differentiation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon