Derivative of ${({tan}^{- 1} x)}^{2}$ wrt to x.

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Solution

The derivatives of ${({tan}^{- 1} x)}^{2}$ is w. r. to x
$\Rightarrow \frac{d ({tan}^{- 1} x)}{d x} = 2 {tan}^{- 1} x \cdot \frac{d {tan}^{- 1} x}{d x} = \frac{2 {tan}^{- 1} x}{(1 + x^{2})}$

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