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Question

Derivative of logxcosx with respect to x is

A
logxcosx[cosxxlogxsinxlog(logx)]
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B
logxcosx[cosxxlogxcosxlog(logx)]
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C
logxsinx[sinxxlogxsinxlog(logx)]
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D
None of these
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Solution

The correct option is C None of these
Let y=logxcosx

y=(cosx)(logx)

dydx=(cosx)(1x)+(sinx)(logx)

=cosxxsinxlogx

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