CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Derivative of logxcosx with respect to x is

A
logxcosx[cosxxlogxsinxlog(logx)]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
logxcosx[cosxxlogxcosxlog(logx)]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
logxsinx[sinxxlogxsinxlog(logx)]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C None of these
Let y=logxcosx

y=(cosx)(logx)

dydx=(cosx)(1x)+(sinx)(logx)

=cosxxsinxlogx

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Special Integrals - 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon